3.291 \(\int (a \cos (e+f x))^m \sqrt {b \csc (e+f x)} \, dx\)

Optimal. Leaf size=78 \[ -\frac {\sin ^2(e+f x)^{3/4} (b \csc (e+f x))^{3/2} (a \cos (e+f x))^{m+1} \, _2F_1\left (\frac {3}{4},\frac {m+1}{2};\frac {m+3}{2};\cos ^2(e+f x)\right )}{a b f (m+1)} \]

[Out]

-(a*cos(f*x+e))^(1+m)*(b*csc(f*x+e))^(3/2)*hypergeom([3/4, 1/2+1/2*m],[3/2+1/2*m],cos(f*x+e)^2)*(sin(f*x+e)^2)
^(3/4)/a/b/f/(1+m)

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Rubi [A]  time = 0.10, antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2586, 2576} \[ -\frac {\sin ^2(e+f x)^{3/4} (b \csc (e+f x))^{3/2} (a \cos (e+f x))^{m+1} \, _2F_1\left (\frac {3}{4},\frac {m+1}{2};\frac {m+3}{2};\cos ^2(e+f x)\right )}{a b f (m+1)} \]

Antiderivative was successfully verified.

[In]

Int[(a*Cos[e + f*x])^m*Sqrt[b*Csc[e + f*x]],x]

[Out]

-(((a*Cos[e + f*x])^(1 + m)*(b*Csc[e + f*x])^(3/2)*Hypergeometric2F1[3/4, (1 + m)/2, (3 + m)/2, Cos[e + f*x]^2
]*(Sin[e + f*x]^2)^(3/4))/(a*b*f*(1 + m)))

Rule 2576

Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b^(2*IntPar
t[(n - 1)/2] + 1)*(b*Sin[e + f*x])^(2*FracPart[(n - 1)/2])*(a*Cos[e + f*x])^(m + 1)*Hypergeometric2F1[(1 + m)/
2, (1 - n)/2, (3 + m)/2, Cos[e + f*x]^2])/(a*f*(m + 1)*(Sin[e + f*x]^2)^FracPart[(n - 1)/2]), x] /; FreeQ[{a,
b, e, f, m, n}, x] && SimplerQ[n, m]

Rule 2586

Int[((b_.)*sec[(e_.) + (f_.)*(x_)])^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Dist[(1*(b*Cos[e +
f*x])^(n + 1)*(b*Sec[e + f*x])^(n + 1))/b^2, Int[(a*Sin[e + f*x])^m/(b*Cos[e + f*x])^n, x], x] /; FreeQ[{a, b
, e, f, m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n] && LtQ[n, 1]

Rubi steps

\begin {align*} \int (a \cos (e+f x))^m \sqrt {b \csc (e+f x)} \, dx &=\frac {\left ((b \csc (e+f x))^{3/2} (b \sin (e+f x))^{3/2}\right ) \int \frac {(a \cos (e+f x))^m}{\sqrt {b \sin (e+f x)}} \, dx}{b^2}\\ &=-\frac {(a \cos (e+f x))^{1+m} (b \csc (e+f x))^{3/2} \, _2F_1\left (\frac {3}{4},\frac {1+m}{2};\frac {3+m}{2};\cos ^2(e+f x)\right ) \sin ^2(e+f x)^{3/4}}{a b f (1+m)}\\ \end {align*}

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Mathematica [A]  time = 1.05, size = 96, normalized size = 1.23 \[ \frac {2 \tan (e+f x) \sqrt {b \csc (e+f x)} \left (-\cot ^2(e+f x)\right )^{\frac {1-m}{2}} (a \cos (e+f x))^m \, _2F_1\left (\frac {1}{4} (1-2 m),\frac {1-m}{2};\frac {1}{4} (5-2 m);\csc ^2(e+f x)\right )}{f (2 m-1)} \]

Antiderivative was successfully verified.

[In]

Integrate[(a*Cos[e + f*x])^m*Sqrt[b*Csc[e + f*x]],x]

[Out]

(2*(a*Cos[e + f*x])^m*(-Cot[e + f*x]^2)^((1 - m)/2)*Sqrt[b*Csc[e + f*x]]*Hypergeometric2F1[(1 - 2*m)/4, (1 - m
)/2, (5 - 2*m)/4, Csc[e + f*x]^2]*Tan[e + f*x])/(f*(-1 + 2*m))

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fricas [F]  time = 0.87, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\sqrt {b \csc \left (f x + e\right )} \left (a \cos \left (f x + e\right )\right )^{m}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cos(f*x+e))^m*(b*csc(f*x+e))^(1/2),x, algorithm="fricas")

[Out]

integral(sqrt(b*csc(f*x + e))*(a*cos(f*x + e))^m, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {b \csc \left (f x + e\right )} \left (a \cos \left (f x + e\right )\right )^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cos(f*x+e))^m*(b*csc(f*x+e))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(b*csc(f*x + e))*(a*cos(f*x + e))^m, x)

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maple [F]  time = 0.16, size = 0, normalized size = 0.00 \[ \int \left (a \cos \left (f x +e \right )\right )^{m} \sqrt {b \csc \left (f x +e \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*cos(f*x+e))^m*(b*csc(f*x+e))^(1/2),x)

[Out]

int((a*cos(f*x+e))^m*(b*csc(f*x+e))^(1/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {b \csc \left (f x + e\right )} \left (a \cos \left (f x + e\right )\right )^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cos(f*x+e))^m*(b*csc(f*x+e))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(b*csc(f*x + e))*(a*cos(f*x + e))^m, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (a\,\cos \left (e+f\,x\right )\right )}^m\,\sqrt {\frac {b}{\sin \left (e+f\,x\right )}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*cos(e + f*x))^m*(b/sin(e + f*x))^(1/2),x)

[Out]

int((a*cos(e + f*x))^m*(b/sin(e + f*x))^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \cos {\left (e + f x \right )}\right )^{m} \sqrt {b \csc {\left (e + f x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cos(f*x+e))**m*(b*csc(f*x+e))**(1/2),x)

[Out]

Integral((a*cos(e + f*x))**m*sqrt(b*csc(e + f*x)), x)

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